this is for the Sin
*Remember that sin = opposite / hypotenuse*
a² + b² = c² (where a and b are legs and c is the hypotenuse)
From the picture, you can see:
a = 3
c = 4
Plug these into the equation and solve for b.
* a² + b² = c² *
step 1: 3² + b² = 4²
step 2: 9 + b² = 16
step 3: b² = 16 - 9
step 4: b² = 7
step 5: √(b²) = √7
step 6: b = ± √7
FOR COS:
From the picture, you can see that if θ is in quadrant II, b has to be negative.
b = -√7 = adjacent
Remember that cos θ = adjacent / hypotenuse.
cos θ = adjacent / hypotenuse
cos θ = (-√7 / 4)
The first thing we must do in this case is to find the area of the smallest square.
For this, we use the following relationship:
A1 / A2 = 4/1
Substituting:
400 / A2 = 4/1
From here, we clear A2:
A2 = (1/4) * (400)
A2 = 100 in ^ 2
We now look for the side of the small square, we use the following relationship:
A = S ^ 2
We cleared S:
S = root (A)
S = root (100)
S = 10 in
Answer:
the side length S of the smaller square is:
S = 10 in
Answer:
An image without anything to explain it
Step-by-step explanation:
Answer:
D) 2.0
Step-by-step explanation:
(square root of 2 times pi)/(square root of 5) = 1.98691765316 (rounded to 2)