Answer:
A(t) = amount remaining in t years
= A0ekt, where A0 is the initial amount and k is a constant to be determined.
Since A(1690) = (1/2)A0 and A0 = 80,
we have 40 = 80e1690k
1/2 = e1690k
ln(1/2) = 1690k
k = -0.0004
So, A(t) = 80e-0.0004t
Therefore, A(430) = 80e-0.0004(430)
= 80e-0.172
≈ 67.4 g
Step-by-step explanation:
Answer:
the answer is(-8)(-12) l think
Answer:
Hello! Your answer would be below!
Step-by-step explanation:
Graph B)
Hope I helped! Ask me anything if you have questions!
Answer:
a = 1 and b = 2
Step-by-step explanation:
Using the Quotient Rule>
d/dx[(sin x)/(2+cos x) ]
= [(2 + cos x) * cosx - sin x * - sin x)] / (2 + cos x)^2
= 2cos x + cos^2x + sin ^2 x) / (2 + cos x)^2
But cos^2x + sin^2x = 1 so we have:
(1 + 2 cos x) / (2 + cos x)^2
- so a = 1 and b = 2.
Answer:
4
Step-by-step explanation:
