Answer:
Step-by-step explanation:
Given a curve defined by the function 2x²+3y²−4xy=36
The total differential of this function with respect to a variable x makes the function an implicit function because it contains two variables.
Differentiating both sides of the equation with respect to x we have:
4x+6ydy/dx-(4xd(y)/dx+{d(4x)/dx(y))} = 0
4x + 6ydy/dx -(4xdy/dx +4y) = 0
4x + 6ydy/dx - 4xdy/dx -4y = 0
Collecting like terms
4x-4y+6ydy/dx - 4xdy/dx = 0
4x-4y+(6y-4x)dy/dx = 0
4x-4y = -(6y-4x)dy/dx
4y-4x = (6y-4x)dy/dx
dy/dx = (4y-4x)/6y-4x
dy/dx = 2(2y-2x)/2(3y-2x)
dy/dx = 2y-2x/3y-2x proved!
Answer:
y = x/10 + 43/10
Step-by-step explanation:
y - y1/ x - x1 = y2 - y1/ x2 - x1
y - 4/ x +3 = 5 - 4/7 + 3
y - 4 / x + 3 = 1/10
10(y - 4) = x + 3
10y - 40 = x + 3
10y = x + 43
y = x/10 + 43/10
Answer:
The model is shown in the attached picture. The solution is 10.
Step-by-step explanation:
There are two way of showing a model for 2×5
- The tape diagram has 2 equal-sized parts of 5
- The tape diagram has 5 equal-sized parts of 2
Both models give the same solution:
- 5+5=10
- 2+2+2+2+2=10
In the attached picture we can show two types of diagram.
3 and what?
if it is 3 and 5 than the answer would be 15
Answer:
a. 6
b. 9
Step-by-step explanation:
a. The product modulo 7 can be found from the product of the individual numbers modulo 7:
(88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7
= (4·4·1·3) mod 7 = 48 mod 7 = 6
__
b. Powers of 4 mod 11 repeat with period 5:
4 mod 11 = 4
4^2 mod 11 = 5
4^3 mod 11 = 9
4^4 mod 11 = 3
4^5 mod 11 = 1
So, 4^83 mod 11 = 4^3 mod 11 = 9
