$\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}$

Second expression:

3 0

1 year ago

I need this, for tomorrow, numbers 12 and 14

chubhunter [2.5K]

The answer for 12 is x>3

The answer for 14 is z<-3

5 0

3 years ago

Can someone help me?

Dvinal [7]

Answer:

Step-by-step explanation:

trust me my guy ik this is ez

8 0

3 years ago