<h3>Given:</h3>
<h3>To find:</h3>
How much is $100 in ZA rands.
<h3>Solution:</h3>
Let the unknown be "x"

We'll have to do cross multiplication.
So we'll have to multiply 100 and 17.


<u>T</u><u>herefore</u><u>,</u><u> </u><u>$</u><u>1</u><u>0</u><u>0</u><u> </u><u>is</u><u> </u><u>1</u><u>7</u><u>0</u><u>0</u><u> </u><u>ZA</u><u> </u><u>rands</u><u>.</u>
Answer:
The interval of increase of g(x) is
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be
, the first derivative of the function is:


The following condition must be met to define the interval of increase:

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

The solution to this inequation is:

Now, the solution to this expression in interval notation is: 
Answer: C 6 cm
Sorry if I’m wrong
-4x+3+2x-6
The answer is -2x-3
Total weight=number of pennies times weight of 1 penny
total weight/weight of 1 penny=number of pennies
636.3/3.03=210
210 pennies