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chubhunter [2.5K]
2 years ago
13

Violet light has a wavelength of 6. 80E-7 m. What is the frequency?

Chemistry
1 answer:
Sever21 [200]2 years ago
5 0

Answer:

violet has a frequency of 668-789 THz :)

Explanation:

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Convert the number 1.17 x 10-4 into standard notation.
Olin [163]

Answer:

11,700

Explanation:

Since the exponent is negative you move the decimal point to the right.

6 0
4 years ago
Dana wants to determine the molar mass of magnesium hydroxide, Mg(OH)2. Which calculation should she use?
aleksandr82 [10.1K]
Answer C. is correct:

(molar mass of Mg) + (2 x molar mass of O) + (2 x molar mass of H)

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3 0
3 years ago
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Which concept describes the formation of four equivalent, single, covalent bonds by carbon in its compounds that resembles metha
Montano1993 [528]
Carbon is special and unique because it is able to form different compounds with a lot of elements, including itself. When it bonds with itself, this is possible because of the concept of hybridization. It is the mixing of atomic orbitals into a new hybrid orbital. In this case, methane is formed through the sp³ hybridization.
4 0
3 years ago
A 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O. Find the mass of sulfur in a sample of CaSO4 with a m
andrey2020 [161]

The mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

<h3>How to calculate mass of an element in a compound?</h3>

According to this question, a 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O.

This means that the mass of sulfur in the 10.4g of CaSO4 is 10.4g - (3.06g + 4.89g) = 10.4g - 7.95g = 2.45g

Next, we calculate the percent ratio of each element in the compound; CaSO4.

  • Ca = 3.06g/10.4g × 100 = 29.42%
  • S = 2.45g/10.4g × 100 = 23.56%
  • O = 4.89g/10.4g × 100 = 47.02%

According to this question, a sample of CaSO4 with a mass of 65.8 g is given. The mass of each element in this compound is as follows:

  • Ca = 29.42/100 × 65.8g = 19.36g
  • S = 23.56/100 × 65.8g = 15.50g
  • O = 47.02/100 × 65.8g = 30.94g

Therefore, the mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.

Learn more about mass at: brainly.com/question/13672279

#SPJ1

5 0
2 years ago
Calculate the concentration (M) of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to
Luda [366]

The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:

m_1v_1 = m_2v_2

Where m_1 is the molarity before dilution, v_1 is the volume before dilution, m_2 is the molarity after dilution, and v_2 is the volume after dilution.

In this case, m_1 = 0.774 M, v_1 = 10.0 mL, v_2 = 100 mL.

m_2 = m_1v_1/v_2

     = 0.774 x 10/100

      = 0.0774 M

Thus, the new concentration of the sodium sulfide solution would be 0.0774 M.

Mole of the final solution: 0.0774 x 0.1 = 0.00774 mol

Sodium sulfide formula = Na_2S ---> 2Na^+ + S^{2-

Equivalent mole of sodium ion = 0.00774 x 2

                                                    = 0.01548 mol

The concentration of sodium ions = mol/volume

                                                  = 0.01548/0.1

                                                  = 0.1548 M

In other words, the concentration of the sodium ions in the diluted solution would be 0.1548 M.

More on dilution can be found here: brainly.com/question/21323871

#SPJ1

6 0
1 year ago
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