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weeeeeb [17]
3 years ago
8

Which concept describes the formation of four equivalent, single, covalent bonds by carbon in its compounds that resembles metha

ne, ch4?
Chemistry
1 answer:
Montano1993 [528]3 years ago
4 0
Carbon is special and unique because it is able to form different compounds with a lot of elements, including itself. When it bonds with itself, this is possible because of the concept of hybridization. It is the mixing of atomic orbitals into a new hybrid orbital. In this case, methane is formed through the sp³ hybridization.
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Which is a binary ionic compound?
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A binary ionic compound is composed of ions of two different elements - one of which is a metal, and the other a nonmetal.

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In a nuclear power plant control rods are used to
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Any two functions of crystals<br>​
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In the laboratory a student combines 26.2 mL of a 0.234 M chromium(III) acetate solution with 10.7 mL of a 0.461 M chromium(III)
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<u>Answer:</u> The molarity of Cr^{3+} ions in the solution is 0.299 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For chromium (III) acetate:</u>

Molarity of chromium (III) acetate solution = 0.234 M

Volume of solution = 26.2 mL

Putting values in equation 1, we get:

0.234=\frac{\text{Moles of chromium (III) acetate}\times 1000}{26.2}\\\\\text{Moles of chromium (III) acetate}=\frac{0.234\times 26.2}{1000}=0.00613mol

1 mole of chromium (III) acetate (Cr(CH_3COO)_3) produces 1 mole of chromium (Cr^{3+}) ions and 3 moles of acetate (CH_3COO^-) ions

Moles of Cr^{3+}\text{ ions}=(1\times 0.00613)=0.00613moles

  • <u>For chromium (III) nitrate:</u>

Molarity of chromium (III) nitrate solution = 0.461 M

Volume of solution = 10.7 mL

Putting values in equation 1, we get:

0.461=\frac{\text{Moles of chromium (III) nitrate}\times 1000}{10.7}\\\\\text{Moles of chromium (III) nitrate}=\frac{0.461\times 10.7}{1000}=0.00493mol

1 mole of chromium (III) nitrate (Cr(NO_3)_3) produces 1 mole of chromium (Cr^{3+}) ions and 3 moles of nitrate (NO_3^-) ions

Moles of Cr^{3+}\text{ ions}=(1\times 0.00493)=0.00493moles

  • <u>For chromium cation:</u>

Total moles of chromium cations = [0.00613 + 0.00493] = 0.01106 moles

Total volume of solution = [26.2 + 10.7] = 36.9 mL

Putting values in equation 1, we get:

\text{Molarity of }Cr^{3+}\text{ cations}=\frac{0.01106\times 1000}{36.9}\\\\\text{Molarity of }Cr^{3+}\text{ cations}=0.299M/tex]Hence, the molarity of [tex]Cr^{3+} ions in the solution is 0.299 M

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2CaO + 2CO2 → 2CaCO2 + O2 is right

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