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Natali5045456 [20]
2 years ago
5

Simplify 8(x + 3) - 2x.Answer options:A) 6 x + 3B) 7 xC) 6 x + 24​

Mathematics
2 answers:
s344n2d4d5 [400]2 years ago
4 0

Answer:

C

Expand the bracets then simplfy and then factorise

TiliK225 [7]2 years ago
3 0
8x+24-2x Propiedad Distributiva
6x+24 Términos semejantes
C
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2 years ago
Which of the following is equivalent to x+1/y divided by g+1/h
Vikki [24]

Answer:

B) x + 1/y times h/g+1

Step-by-step explanation:

We need to divide \frac{x+1}{y} by \frac{g+1}{h} then match with given choices to find the correct equivalent result.

where given choices are:

A) x/y times h/g

B) x + 1/y times h/g+1

C) x+ 1/y divided h/g+1

D) y/x+1 divided g+1/h

So let's divide  \frac{x+1}{y} by \frac{g+1}{h}

\frac{\left(\frac{x+1}{y}\right)}{\left(\frac{g+1}{h}\right)}

we are allowed to flip the bottom fraction and change division sign into multiplication. So we get:

=\left(\frac{x+1}{y}\right)\cdot\left(\frac{h}{g+1}\right)

Hence correct choice is: B) x + 1/y times h/g+1

3 0
3 years ago
If k(t)=3/4t-3 what is the value of k(-12)?
Valentin [98]

Answer:

-3.0625

Step-by-step explanation:

just plug in -12

3/4t-3

3/2(-12)-13

then solve to get -3.0625 or -3.06

and this is how you solve any problem like this.

8 0
3 years ago
Help appreciated on question in image!<br> Thanks:)
Verdich [7]

Answer:

x=-1,\:x=-7,\:x=i,\:x=-i

Step-by-step explanation:

Considering the equation

x^4+8x^3+8x^2+8x+7=0

Solving

x^4+8x^3+8x^2+8x+7

\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)

As

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=7,\:\quad a_n=1

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

Solving

\frac{x^4+8x^3+8x^2+8x+7}{x+1}

=x^3+7x^2+x+7

Putting \frac{x^4+8x^3+8x^2+8x+7}{x+1} =  x^3+7x^2+x+7 in equation [A]

So,

\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

=\left(x+1\right)x^3+7x^2+x+7

As

x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)

So,

Equation [A] becomes

=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)

So,  the polynomial equation becomes

\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)\mathrm{Solve\:}\:x+1=0:\quad x=-1

\mathrm{Solve\:}\:x+7=0:\quad x=-7

\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i

\mathrm{The\:solutions\:are}

x=-1,\:x=-7,\:x=i,\:x=-i

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

#learnwithBrainly

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3 years ago
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