A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height 
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t


Solve for t


Solve using quadratic formula


After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
Answer:
y=-5x+1
Step-by-step explanation:
plug the coordinate points to the equation, and find your y intercept
Hello!
Let's find the area and see!
A = s^2
A = 3^2
A = 6 ft^2
Now, if you double 3, you get 6. 3 × 2 = 6 Find the area:
A = 6^6
A = 36 ft^2
ANSWER:
No, the area will not be doubled. The area was 9 ft^2 when the sides were 3 feet long. If you double 9, you get 18, since 9 × 2 = 18.
36 is not the double of 9, so no, the area is not double.
Answer:
A. 25.7°
Step-by-step explanation:
the sum of straight angle is 180°.
so, i subtract 154.3 from 180.
i get 25.7 °