M<1 = 1/2(b-d)
answer is C. third choice
<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer:
x
=
ln
(
3
)
7
ln
(
3
)
+
ln
(
7
)
Step-by-step explanation:
Answer:
Below
Step-by-step explanation:
Difference= ‘-’
=
