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olchik [2.2K]
2 years ago
11

Which one are correct?

Mathematics
1 answer:
Nesterboy [21]2 years ago
8 0
B and d are correct
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A class consists of 1/2 freshmen, 1/8 sophomores, and 1/8 juniors; the rest are seniors. What fraction of the class is seniors?
Firlakuza [10]

Answer:

2/8

Step-by-step explanation:

freshman=4/8

1/8 soph    1/8 jr

add all together u get 6/8

the rest is seniors so its 2/8

8 0
3 years ago
What is the force of a 12 kg object that is accelerating at a rate of 6 m/s2?
Leviafan [203]

Answer:

force= mass × acceleration

12×6

72 N

7 0
3 years ago
A hockey team won 6 games and lost 8 what is the ratio of wins to number of games
suter [353]

Answer:

6:8

Step-by-step explanation:

you take the number of wins and put it against the number of losses. If it has to be percentage of games won you would do 6: 14 or number of games won compared to total number of games

6 0
3 years ago
Read 2 more answers
What is the y intercept, and what does it represent?
motikmotik
In the linear equation y = mx + b, y-intercept represents the value of y. It is the point where the line crosses the y-axis(vertical axis)

Finding the y-intercept is done by looking at which point in the graph crosses the y-axis. This point will always have an x-coordinate of zero(0).
4 0
3 years ago
Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
trasher [3.6K]
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
4 0
3 years ago
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