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kogti [31]
2 years ago
7

Multiply y^2-9/-2y*-5y/y+3

Mathematics
2 answers:
kykrilka [37]2 years ago
4 0

Answer:

\huge\boxed{\dfrac{-5(y-3)}{-2}}

Step-by-step explanation:

\dfrac{y^2-9}{-2y}\cdot\dfrac{-5y}{y+3}=\dfrac{y^2-3^2}{-2y}\cdot\dfrac{-5y}{y+3}

use: a² - b² = (a - b)(a + b)

=\dfrac{(y-3)(y+3)}{-2y}\cdot\dfrac{-5y}{y+3}

simplify fractions

(y + 3) and y

=\dfrac{y-3}{-2}\cdot\dfrac{-5}{1}=\dfrac{-5(y-3)}{-2\cdot1}=\dfrac{-5(y-3)}{-2}

erik [133]2 years ago
3 0

Answer:

-5(y - 3)/-2

Step-by-step explanation:

y² - 9/-2y × -5y/y + 3

Multiply Rewrite

Simplify the expression

(y - 3)×(y + 3)/2 × 5/y + 3

Simplify the expression

y - 3/2 × 5

Calculate

5(y - 3)/2

HOPE THIS HELPS :)

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