With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
Answer:
<h2>45, 46, 47</h2>
Step-by-step explanation:
n, n + 1, n + 2 - three consecutive integers
The equation:
138 - n = (n + 1) + (n + 2)
138 - n = n + 1 + n + 2 <em>combile like terms</em>
138 - n = 2n + 3 <em>subtract 138 from both sides</em>
-n = 2n - 135 <em>subtract 2n from both sides</em>
-3n = -135 <em>divide both sides by (-3)</em>
n = 45
n + 1 = 46
n + 2 = 47
Answer:
x - y + z = 8
2x +3y -z= -2
3x - 2y -9z = 9
Step-by-step explanation:
[1 - 1 1 8]
[2 3 -1 -2]
[3 -2 -9 9]
2(5x^2+2x)+2(3x^2)
10x^2+4x+6x^2
16x^2+4x
D is the correct answer.
Step-by-step explanation:
4x=3x
2+4x=3x+2
4x-3x=2-2
1x=0
x=1/0
X=0
(i think the question given was incomplete but this waht i could do with the given statement)
