(a) No. The probability of drawing a specific second card depends on the identity of the first card.
Two events are independent if knowledge on the first doesn't change anything about the probability distribution of the second event. This isn't the case: since you don't replace the first card, you have some extra knowledge about the second.
If, for example, you pick the 7 of hearts at the beginning, you are sure that the second card won't be the 7 of hearts. This extra piece of information depends on the first pick, and so the two pick are not independent: knowledge about the first pick changed what you expect from the second pick.
(b)
The probability of finding ace on 1st card is 4/52 = 1/13, because there are four aces (one for each suit) out of 52 cards. If this happens, you're left with 51 cards, 4 of which are kings (one for each suit). So, the probability of picking a king among the remaining cards is 4/51. The probability of the two happening one after the other is
(c)
You can use the same logic as point (b)
(d)
We have 8 "good" cards for the first pick: any of the 4 aces or any of the 4 kings. So, the first pick has a success rate of 8/52 = 2/13. For the second pick we have 4 "good cards" (the 4 aces if we picked a king, the 4 kings if we picked an aces) out of the 51 remaining cards, so we have a success rate of 4/51. So, the probability of picking an ace and a king, in any order, is
1720 ft^2 you just need to times all the numbers together.
Answer:
idk
Step-by-step explanation:
i wish i did
as the product of 90 degrees and 20 degrees
30x60=1800
90x20=1800