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Ierofanga [76]
2 years ago
12

Three dice, each with faces numbered 1 through 6, are arranged as shown. Seven faces are visible. Find the sum of the numbers on

all the faces that are not visible.

Mathematics
2 answers:
In-s [12.5K]2 years ago
6 0
The Answer for your math problem is 37
PolarNik [594]2 years ago
3 0

Answer:

37

Step-by-step explanation:

First, we need to find the sum of all the numbers of the dice. The expression 3(1 + 2 + 3 + 4 + 5 + 6), or 3(21) does that for us. 3 × 21 = 63. So the sum of all of the numbers of the dice is 63. But we already know 7 of the numbers there: 2, 3, 1, 6, 5, 4, 5. In the expression 3(21), we counted these numbers as well. So now we can add these 7 numbers together then subtract them from 3(21), or 63. We can write the expression 3(21) - (2 + 3 + 1 + 6 + 5 + 4 + 5), or 3(21) - 26 = 63 - 26 = 37.

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