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Assoli18 [71]
3 years ago
11

Subtract polynomials (intro)

Mathematics
1 answer:
ELEN [110]3 years ago
4 0

Answer:

The result in standard form is:

\left(-5t+4t^2-t\right)-\left(8t^2+t\right)=-4t^2-7t

Step-by-step explanation:

Given the polynomials

  • -5t+ 4t² – t
  • 8t² + t

subtracting 8t² + t from -5t+ 4t² – t.

\left(-5t+\:4t^2\:-\:t\right)\:-\:\left(8t^2\:+\:t\right)

Remove parenthese: (-a) = -a

i.e. - (8t² + t) = 8t² - t

so the expression becomes

=-5t+4t^2-t-8t^2-t        

grouping the like terms

=4t^2-8t^2-5t-t-t

Add similar elements: 4t² - 8t² = -4t²

=-4t^2-5t-t-t

Add similar elements: -5t - t - t = -7t

=-4t^2-7t

Therefore, the result in standard form is:

\left(-5t+4t^2-t\right)-\left(8t^2+t\right)=-4t^2-7t

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The polygon circumscribes the circle. Which of the following is the perimeter of the polygon?
dolphi86 [110]

The perimeter of the polygon that circumscribes the circle is 78 cm

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle tangent theorem states that tangents which meet at the same point are equal in length. Hence:

The missing lengths are 8, 6, 9 and 16.

Perimeter of the polygon = 2(8) + 2(6) + 2(9) + 2(16) = 78 cm

The perimeter of the polygon that circumscribes the circle is 78 cm

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4 0
1 year ago
Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

Choose the first alternative

7 0
3 years ago
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Square root of 6 minus square root of 7 divided by square root of 6 plus square root of 7
zheka24 [161]
\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \\ &#10; Multiply \ and \ divide \ by \ the \ conjugate. \\ &#10; =\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \times \ \frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}- \sqrt{7} } \\ &#10;=
\frac{( \sqrt{6}- \sqrt{7})^2 }{ \sqrt{6}^2 - \sqrt{7}^2 }} \\ &#10; =\frac{( \sqrt{6}- \sqrt{7})^2 }{-1} \\ &#10; =-( \sqrt{6}- \sqrt{7})^2 \\ &#10; = -( \sqrt{6}^2-2( \sqrt{6} \sqrt{7}+ \sqrt{7}^2 \\ &#10; =-(6 -2 \sqrt{42} +7) \\ &#10; =-6+2 \sqrt{42}-7 \\ &#10; =-13+2 \sqrt{42} \\ &#10;Answer: \ -13+2 \sqrt{42}

6 0
3 years ago
Factor completely x^2-48
fredd [130]

Answer: (x-7)(x+7)


Step-by-step explanation:

To solve this problem you must apply the proccedure shown below;

- Make the equation equal to zero:

x^{2}-49=0

-Add 49 at both sides:

x^{2}=49

- Now, you must take the square root of both sides of the equation, then you obtain the following roots:

x=\sqrt{49}\\x_1=7\\x_2=-7

- Then you have:

x^{2}-49=(x-7)(x+7)

5 0
3 years ago
Please someone help me!! will give first person brainliest!!
svet-max [94.6K]

3.) (3,9)

4.) (-3,11)

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