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OlgaM077 [116]
2 years ago
13

Answer answer question please

Mathematics
2 answers:
xeze [42]2 years ago
6 0

Answer:

a

Step-by-step explanation:

it says 3 and 2/5ths

hope this helps

sophia

Fittoniya [83]2 years ago
4 0

Answer:

Step-by-step explanation:

3 and 2/5

(aka A)

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I rlly need help! pleas help quick!
Serggg [28]

Answer:

2^9 or 512

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Use the diagram to find lengths. BP is the perpendicular bisector of AC. QC is the
faust18 [17]

Answer:

The length of the side PC is 34 cm.

Step-by-step explanation:

We are given that BP is the perpendicular bisector of AC. QC is the perpendicular bisector of BD. AB = BC = CD.

Suppose BP = 16 cm and AD = 90 cm.

As, it is given that AD = 90 cm and the three sides AB = BC = CD.

From the figure it is clear that AD = AB + BC + CD

So, AB = \frac{90}{3} = 30 cm

BC = \frac{90}{3} = 30 cm

CD = \frac{90}{3} = 30 cm

Since the triangle, BPC is a right-angled triangle as \anglePBC = 90°, so we can use Pythagoras theorem in this triangle to find the length of the side PC.

Now, the Pythagoras theorem states that;

\text{Hypotenuse}^{2} = \text{Perpendicular}^{2} +\text{Base}^{2}

\text{PC}^{2} = \text{BP}^{2} +\text{BC}^{2}

\text{PC}^{2} = \text{16}^{2} +\text{30}^{2}

\text{PC}^{2} = 256+900 = 1156

\text{PC}=\sqrt{1156}

PC = 34 cm

Hence, the length of the side PC is 34 cm.

4 0
3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
Read 2 more answers
If my assignment is worth 14% of my quiz weight which is 27% of my total weight what is the weight of that assignment
Nimfa-mama [501]

Answer:

3.785%

Step-by-step explanation:

Assignment is 14% of the quiz

=> Assignment = 14% of the quiz

Quiz is 27% of the total weightage

=> 14% of 27%

<u>Find 14% of 27% </u>

14% of 27%

= 0.14 x 27 = 3.785%

The assignment is 3.785% of the total weightage.

6 0
3 years ago
Solve these for points<br> I5 - 9I = <br> I5I - I9I =
Aleksandr-060686 [28]
|5-9| = 4

|5| - |9| = -4
4 0
3 years ago
Read 2 more answers
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