Use the equation
A= 2(wl +hl +hw)
Where
w is width
h is height
l is length

y - y₁ = m(x - x₁)
y - (-10) = -1⁴/₂₁(x - 6)
y + 10 = -1⁴/₂₁(x) + 1⁴/₂₁(6)
y + 10 = -1⁴/₂₁x + 7¹/₇
- 10 - 10
y = -1⁴/₂₁x - 3¹/₇
Answer:
<h3>20feet</h3>
Step-by-step explanation:
Initial height of the ball = 8feet
If it bounces 60% of its previous height, its new height will be;
60% of 8
= 60/100 * 8
= 480/100
= 4.8 ft
If it bounces 60% of its current distance, new height will be expressed as;
60% of 4.8
= 0.6 * 4.8
= 2.88
The height of the ball will keep reducing and form a geometric progression of the form 8, 4.8, 2.88...
In order to get the total distance traveled by the ball, we need to calculate the sum to infinity of the sequence;
S∞ = a/1-r where;
a is the first term = 8
r is the common ratio

Substitute into the formula;
S∞ = a/1-r
S∞ = 8/1-0.6
S∞ = 8/0.4
S∞ = 20feet
Hence the total distance traveled by the ball is 20feet
"<span>a number that is equal to five less than b"
</span>n-a number
n = b - 5