The roots routine will return a column vector containing the roots of a polynomial. The general syntax is
z = roots(p)
where p is a vector containing the coefficients of the polynomial ordered in descending powers.
Given a vector
which describes a polynomial
we construct the companion matrix (which has a characteristic polynomial matching the polynomial described by p), and then find the eigenvalues of it (which are the roots of its characteristic polynomial)
Example
Here is an example of finding the roots to the polynomial
--> roots([1 -6 -72 -27])
ans =
12.1229
-5.7345
-0.3884
Answer:
A= 4
sq. unit
Step-by-step explanation:
The answer is in the attached picture.
Answer:
x = 1.5 ; y = -0.5
Step-by-step explanation:
2x + 4y = 1 ---------------------(i)
3x - 5y =7 ----------------------(ii)
(i) * 5 10x + 20y = 5
(ii)*4 <u> 12x -20y = 28 </u>
add, 22x = 33 { here y will be eliminated}
x = 33/22 = 3/2
x = 1.5
Put the value of x in equation (i)
2*1.5 + 4y = 1
3 + 4y = 1
4y = 1-3
4y = -2
y = -2/4 = -1/2
y = -0.5
Answer:
x=7; NL=12; NP+20
Step-by-step explanation:
