H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
Answer:
70°
Step-by-step explanation:
Since ∠BCA is supplementary with the 110° angle shown on the other side, ∠BCA = 180° (The measurement of a straight line) - 110° = 70°.
~Hope this helps!~
Answer:
C) translated 1 unit to the left and then rotated 180° counterclockwise about the origin
Step-by-step explanation:
by inspection, shape A has been translated 1 unit to the left and then rotated 180° counterclockwise about the origin
Answer:
the difference represents translations
Step-by-step explanation:
if you're talking about edmentum geometry unit 8, then the difference should be in how far apart each point is
Answer:
How does it need solved? By graphing? Substitution?
Step-by-step explanation:
