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1 year ago

What is the circumference of a circle with a diameter of 85 feet? feet (Use 3.14 for Pi.)

2 answers:

4 0

Answer: 266.9 ft

Step-by-Step Solution:

d = 85 ft
r = 85/2 = 42.5 ft

Circumference = 2πr

Therefore,
= 2πr
= 2 * π * r
= 2 * 3.14 * 42.5
= 6.28 * 42.5
= 266.9

=> Circumference = 266.9 ft

joja [24]1 year ago

3 0

Answer:

266.9 feet

thats the answer

sana makatulong poww huhu

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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3 years ago

Read 2 more answers

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IRINA_888 [86]

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Step-by-step explanation:

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3 years ago

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Troyanec [42]

Answer:

$\large\boxed{A.\ f(x)+g(x)=9x^2-x-3}\\\boxed{B.\ f(x)-g(x)=5x^2-9x+9}\\\boxed{g(x)-f(x)=-5x^2+9x-9}$

Step-by-step explanation:

$f(x)=7x^2-5x+3,\ g(x)=2x^2+4x-6\\\\A:\\f(x)+g(x)=(7x^2-5x+3)+(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3+2x^2+4x-6\qquad\text{combine like terms}\\f(x)+g(x)=(7x^2+2x^2)+(-5x+4x)+(3-6)\\f(x)+g(x)=9x^2-x-3$

$B:\\f(x)-g(x)=(7x^2-5x+3)-(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3-2x^2-4x+6\qquad\text{combine like terms}\\f(x)-g(x)=(7x^2-2x^2)+(-5x-4x)+(3+6)\\f(x)+g(x)=5x^2-9x+9$

$C:\\g(x)-f(x)=(2x^2+4x-6)-(7x^2-5x+3)\\g(x)-f(x)=2x^2+4x-6-7x^2+5x-3\qquad\text{combine like terms}\\g(x)-f(x)=(2x^2-7x^2)+(4x+5x)+(-6-3)\\g(x)-f(x)=-5x^2+9x-9$

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