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snow_lady [41]
2 years ago
12

The lengths of the sides of an equilateral triangle are 3(x + )cm, (5x +2y-1) cm and 5x +1 Cm Find the side length of the triang

le. ​
Mathematics
1 answer:
pochemuha2 years ago
5 0

Answer:

Correct option is A

Since it is an equilateral triangle, the lengths of the sides are equal

So, x+3 y=3 x+2 y−2=4 x+

2

1

​

y+1

x+3 y=3 x+2 y−2

y=2 x−2

2 x−y=2 ...(1)

Also, 4 x+

2

1

y+1=x+3 y

8 x+y+2=2 x+6 y

6 x+2=5 y

6 x−5 y=−2   ...(2)

Multiplying e q(1) by  5 we get,

10 x−5 y=10      ...(3)

Subtracting e q(2) from e q(3) we get,

4 x=12⇒x=3

y=2 x−2=4

The length of one side of equilateral triangle = x+3 y =3+3(4)=15 units

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3 years ago
Just need to know how to solve
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Step-by-step explanation:

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Graph a line that is parallel to the given line. Determine the slope ofthe given line and the one you graphed in simplest form.
Daniel [21]

original slope = -4/3

parallel slope = -4/3

Explanation:

For a line to be parallel to anpother line, the slope of both lines must be equal.

We need to find the slope of the given line by picking any two points on the line.

Using points (-6, 5) and (0, -3)

slope formula:

m\text{ = }\frac{y_2-y_1}{x_2-x_1}\begin{gathered} x_1=-6,y_1=5,x_2=0,y_2\text{ = -}3 \\ \text{slope = m= }\frac{-3-5}{0-(-6)}=\frac{-8}{0+6} \\ m\text{ = -8/6} \\ m\text{ = -4/3} \end{gathered}

The equation of the given line: y = mx + b

b = y-intercept = -3

y = -4/3x - 3

The equation line parallel to the one above could be:

y = -4/3 x + 7

This because the slope are the same

original slope = -4/3

parallel slope = -4/3

plotting the graph of the lline parallel to the first one:

3 0
1 year ago
What is the surface area of the triangular prism shown?
Lunna [17]

Answer:

The first step that we are going to do is to solve the area of the top rectangle.  We are given a width of 15 cm and a length of 25 cm so we can just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 15\ cm

Area = 375\ cm^2

The second side that we are going to solve for is the bottom rectangle.  We are given a width of 12 cm and a length of 25 cm so lets just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 12\ cm

Area = 300\ cm^2

The next area that we are going to determine is the back rectangle which has a width of 9 cm and a length of 25 cm so lets just multiply them against each other to get the area.

Area = l * w

Area = 25\ cm * 9\ cm

Area = 225\ cm^2

The final area that we have to determine are the side triangles.  After determining the area of one triangle we will have to multiply it by 2 to get the area for both of the triangles.  We are given a base of 12 cm and a height of 9 cm so lets just use the formula to find the area.

Area = \frac{1}{2}* b*h

Area = \frac{1}{2}* 12\ cm*9\ cm

Area = 54\ cm^2

Multiply it by two to get the area for both of the triangles.

Area = 54\ cm^2 * 2

Area = 108\ cm^2

Finally, we are onto the last part which is to add up all of the areas and get the surface area after we combine everything.

Area_{total}=375\ cm^2 + 300\ cm^2 + 225\ cm^2 + 108\ cm^2

Area_{total}=1008\ cm^2

Therefore, our final answer is option B, 1008 cm^2

Hope this helps!

4 0
2 years ago
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