Answer:
x=6/11
x≈0.545
Step-by-step explanation:
They are corresponding angles, so their measurements are congruent to each other. Therefore, you can set them equal to each other and solve for x:
19x+6=30x
6=11x
6/11=x
x=6/11
x≈0.545
This involves basic arithmetic calculations and simultaneous equations.
Adamu has 25 Cards
Let the following letters represent the number of cards each has;
A: ADAMU
F: FUNKE
S: SHEHU
K: KWAME
T: TANKO
- If adamu gives funke 5 cards, he will have as many as tanko. Thus;
A - 5 = T --- eq 1
- If funke gives adamu 4 cards, he will have as many as kwame. Thus;
A + 4 = K --- eq 2
- Funke and adamu have a total of 13 more cards than the total that kwame and tanko have. Thus;
A + F = K + T + 13 --- eq 3
- Adamu has 2 cards more than what Shehu has. Thus;
A - 2 = S --- eq 4
From online research, the Total Number of cards is 134 and not 133. Thus;
A + F + K + S + T = 134 --- eq 5
Let's put A - 5 = T and A + 4 = K in eq 3 to get;
A + F = (A + 4) + (A - 5) + 13
A + F = 2A + 12
F = 2A - A + 12
F = A + 12
Let's put A - 2 = S ; F = A + 12 ; A - 5 = T and A + 4 = K into eq 5 to get;
A + A + 12 + A + 4 + A - 2 + A - 5 = 134
Simplifying gives;
5A + 9 = 134
5A = 134 - 9
5A = 125
A = 125/5
A = 25
Adamu has 25 Cards
Answer: is Aaaaaaa
Step-by-step explanation:
Answer:
x greater than or equal to 5
Answer:
The answer is C.
Step-by-step explanation:
Given the line segment ST. we have to give the instruction to construct the perpendicular bisector of line ST.
So to construct the perpendicular bisector of line our first step is to place the compass at one end of line and then adjust the compass more than half of line segment and draw the arc on each side of segment.
After that Keeping the same compass width, draw arcs from other end of line. Place scale where the arcs intersect, and draw the line segment.
So, the correct match is option C ) Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point T than to point S. Draw an arc on each side of segment.
