When three squares are joined at their vertices to form a right triangle, the combined area of the two smaller squares is the sa
me as the area of the largest square. Which three squares will support this statement?
2 answers:
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Answer:
Step-by-step explanation:
Move all terms to one side
4x^2 + 4x + 5 = 0
Plug into quadratic formula
x = (-4 <u>+</u> ) / 2(4)
= (-4 <u>+</u> )/8
At this point, there are no real answers. The roots to this equation are complex.
x = (-4 <u>+</u> 8i)/8
= (-1 <u>+</u> 2i)/2