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3 years ago

5

Henri’s potato vine is growing like crazy! When he planted it, it was 15 inches long. Two weeks later, it was 22 inches long. Fo

ur weeks after that, it was 36 inches long. Write an equation to represent this situation.

1 answer:

telo118 [61]3 years ago

4 0

Answer:

<em>1x = 7</em>

Explanation:

Every week it grows 7 total inches. So, "x" stands for week. The equation "1x = 7" means 1 week equals 7 inches. This is the simplest equation to write this problem.

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If 76+2f(x)+x^2(f(x))^3=0 and f(3)=-2, find f'(3).<br><br> f'(3)=

forsale [732]

2f'(x)+2x(f(x))^3+3x^2(f'(x))=0
f(3)=-2, x=3
2f'(3)+2*3*-2^3+3*-2^2*f'(3)=0
2f'(3)-48+12f'(3)=0
14f'(3)=48
f'(3)=48/14=24/7

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3 years ago

PLZ HELP WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST What is the slope-intercept form of the equation of the line that passes

grigory [225]

Answer:

A.

Step-by-step explanation:

We are given the two points (2,7) and (4,-1). In order to determine the linear equation, we need to find the slope and the y-intercept. First, find the slope <em>m.</em> Let (2,7) be x1 and y1, and let (4,-1) be x2 and y2:

$m=\frac{y_2-y_1}{x_2-x_1} =\frac{-1-7}{4-2}=-8/2=-4$

Thus, the slope is -4.

Now, to find the y-intercept, we can use the point-slope form. Recall that the point slope form is:

$y-y_1=m(x-x_1)$

Where (x1, y1) is a coordinate pair and m is the slope.

Use either of the two coordinate pair. I'm going to use (2,7). Substitute them for x1 and y1, respectively:

$y-(7)=-4(x-(2))\\y-7=-4x+8\\y=-4x+15$

This is also slope-intercept form. The answer is A.

7 0

3 years ago

Read 2 more answers

Simplify.<br> <img src="https://tex.z-dn.net/?f=m%5Csqrt%7Bp%7D%20%2B%20n%5Csqrt%7Bp%7D%20-%20%5Csqrt%7Bp%7D" id="TexFormula1" t

madreJ [45]

Answer:

First option is the correct answer.

$(m + n - 1) \sqrt{p}$

Step-by-step explanation:

$m\sqrt{p} + n\sqrt{p} - \sqrt{p} \\ \\ = (m + n - 1) \sqrt{p}$

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3 years ago

If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?

enyata [817]

Step-by-step explanation:

$\bf➤ \underline{Given-} \\$

$\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\$

$\bf➤ \underline{To\: find-} \\$

$\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\$

$\bf ➤\underline{Solution-} \\$

<u>Let us assume that:</u>

$\rm: \longmapsto u = {x}^{2013}$

<u>Therefore, the equation becomes:</u>

$\rm: \longmapsto u + \dfrac{1}{u} = 2$

$\rm: \longmapsto \dfrac{ {u}^{2} + 1}{u} = 2$

$\rm: \longmapsto{u}^{2} + 1 = 2u$

$\rm: \longmapsto{u}^{2} - 2u + 1 =0$

$\rm: \longmapsto {(u - 1)}^{2} =0$

$\rm: \longmapsto u = 1$

<u>Now substitute the value of u. We get:</u>

$\rm: \longmapsto {x}^{2013} = 1$

$\rm: \longmapsto x = 1$

<u>Therefore:</u>

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 1 + 1$

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 2$

★ <u>Which is our required answer.</u>

$\textsf{\large{\underline{More To Know}:}}$

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

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3 years ago

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lana66690 [7]

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3 years ago

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