By using the AAA congruence property of Triangles, △aec≅△deb is proved
It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad
Also, it is given that,
ca ║db
We need to prove that, △aec≅△deb
Then we'll use AAA congruence property of Triangles to prove the situation
As ca ║db
then, ∠cae = ∠ebd (Alternate angles)
∠ace = ∠edb (Alternate angles)
and ∠aec = ∠deb (common angles)
Thus, by AAA congruence property, △aec≅△deb
Hence, proved
To learn more about, congruence property, here
brainly.com/question/2039214
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