There is no sum for this geometric series. it diverges rather than converges due to the absolute value of the common ratio (r), which is -3, being 3. for a geometric series to have a sum (to converge), the absolute value of r must be less than 1.
(you find r by dividing a2/a1, a3/a2, etc.)
hope this helps
1 allalalalslallalalalslslls
I think it’s a but I don’t know if it’s right
Answer:
it is either the dice or the cups
Step-by-step explanation: