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lutik1710 [3]
3 years ago
6

Can someone help me solve by showing me how to..

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0

Answer:

#15) B. 41

#16. A. 6

Step-by-step explanation:

<h2>#15:</h2>

You are given the Pythagorean Theorem: a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse of the right triangle.

In problem 15, x is the hypotenuse and 9 and 40 are the legs, so you can substitute these values into the formula and solve for c (x).

  • (9)^2 + (40)^2 = c^2

Evaluate the exponents.

  • 81 + 1600 = c^2

Add the like terms together.

  • 1681 = c^2

Square root both sides of the equation.

  • c = 41

Since c = x, the answer for #15 is b. 41.

<h2>#16:</h2>

x and 8 are the legs and 10 is the hypotenuse, so substitute these values into the formula. Make x = a.

  • a^2 + (8)^2 = (10)^2

Evaluate the exponents.

  • a^2 + 64 = 100

Subtract 64 from both sides of the equation.

  • a^2 = 36

Square root both sides of the equation.

  • a = 6

The answer is A. 6.

hichkok12 [17]3 years ago
3 0

15. \:  x =  \sqrt{ {9}^{2} +  {40}^{2}  }  =  \sqrt{81 + 1600}  =  \sqrt{1681}  = 41 \\ 16. \: x =  \sqrt{ {10}^{2} -  {8}^{2}  }  =  \sqrt{100 - 64}  =  \sqrt{36}  = 6

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Meaghan and Lily are dividing 43.61 by 7. Meaghan says that the first digit of the quotient is in the ones place. Lily says it i
Ivahew [28]

Answer: Meaghan is right.

Step-by-step explanation:

For a number like:

123.45

the tens place would be the "2" (second number at the left of the decimal point)

The ones place would be the "3" (first number at the left of the decimal point)

Let's suppose that Lily is correct.

Then the quotient of:

43.61/7

Will be a number with two digits in the left of the decimal point.

The smallest number that meets this condition, is the number 10.

Then let's see:

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and:

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then:

43.61/7 < 70/7 = 10

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Then Meaghan is the correct one.

We also could perform the quotient to find:

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3 years ago
If the radius of a circle is 3 meters, how long is the arc subtended by an angle measuring 30°?
FromTheMoon [43]
Circumference of entire circle = 2 * PI * radius
2 * PI * 3 = <span> <span> <span> 18.8</span></span></span>5 meters
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3 years ago
If (x-1)(x+5)=(x-h)^2+K then what is the value of h
vivado [14]
Solve for h:   (I'm using the completing the square)
(x - 1) (x + 5) = K + (x - h)^2
(x - 1) (x + 5) = K + (x - h)^2 is equivalent to K + (x - h)^2 = (x - 1) (x + 5):
K + (x - h)^2 = (x - 1) (x + 5)
Subtract K from both sides:
(x - h)^2 = (x - 1) (x + 5) - K
Take the square root of both sides:
x - h = sqrt((x - 1) (x + 5) - K) or x - h = -sqrt((x - 1) (x + 5) - K)
Subtract x from both sides:
-h = sqrt((x - 1) (x + 5) - K) - x or x - h = -sqrt((x - 1) (x + 5) - K)
Multiply both sides by -1:
h = x - sqrt((x - 1) (x + 5) - K) or x - h = -sqrt((x - 1) (x + 5) - K)
Subtract x from both sides:
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Solve for h: using the quadratic formula)
(x - 1) (x + 5) = K + (x - h)^2
(x - 1) (x + 5) = K + (x - h)^2 is equivalent to K + (x - h)^2 = (x - 1) (x + 5):
K + (x - h)^2 = (x - 1) (x + 5)
Expand out terms of the left hand side:
h^2 + K - 2 h x + x^2 = (x - 1) (x + 5)
Subtract (x - 1) (x + 5) from both sides:
h^2 + K - 2 h x + x^2 - (x - 1) (x + 5) = 0
h = (2 x ± sqrt(4 x^2 - 4 (K + x^2 - (x - 1) (x + 5))))/2:
<span>Answer:  h = x + sqrt(-5 - K + 4 x + x^2) or h = x - sqrt(-5 - K + 4 x + x^2)</span>
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