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3 years ago

Can someone help me solve by showing me how to..

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

7 0

Answer:

#15) B. 41

#16. A. 6

Step-by-step explanation:

You are given the Pythagorean Theorem: a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse of the right triangle.

In problem 15, x is the hypotenuse and 9 and 40 are the legs, so you can substitute these values into the formula and solve for c (x).

(9)^2 + (40)^2 = c^2

Evaluate the exponents.

81 + 1600 = c^2

Add the like terms together.

1681 = c^2

Square root both sides of the equation.

c = 41

Since c = x, the answer for #15 is b. 41.

x and 8 are the legs and 10 is the hypotenuse, so substitute these values into the formula. Make x = a.

a^2 + (8)^2 = (10)^2

Evaluate the exponents.

a^2 + 64 = 100

Subtract 64 from both sides of the equation.

a^2 = 36

Square root both sides of the equation.

a = 6

The answer is A. 6.

hichkok12 [17]3 years ago

3 0

$15. \: x = \sqrt{ {9}^{2} + {40}^{2} } = \sqrt{81 + 1600} = \sqrt{1681} = 41 \\ 16. \: x = \sqrt{ {10}^{2} - {8}^{2} } = \sqrt{100 - 64} = \sqrt{36} = 6$

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Explain why the mapping diagram below represents a function.

tiny-mole [99]

Answer:

Because there is only one out put for each domain this mapping diagram is a function.

Step-by-step explanation:

Two sets are involved. There is a directional property, the relation is defined from one set called the domain on to another set called the codomain. A function is a relation that has exactly one output for each input in the domain.

6 0

3 years ago

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: