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kap26 [50]
3 years ago
8

Help will mark Brainliest!!​

Mathematics
2 answers:
GuDViN [60]3 years ago
7 0

Answer:

8/9n - 3

Step-by-step explanation:

Licemer1 [7]3 years ago
4 0
The answer is 8/9n - 1 1/3.

Explanation:

When multiplying a fraction by a whole number, you multiply the numerator by the whole number. In this case, doing so would result in 8/9n. Because the same principle would apply for the other part of the equation, we can do 4/9 x -3 to get -12/9. -12/9 is improper, so we could standardize it to get the equation’s expression in simplified form. -12/9 simplified is -1 1/3. The answer would be 8/9n - 1 1/3 because when there is a negative factor, the expression becomes a subtraction problem. Thus, your equation is 8/9n - 1 1/3.
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VladimirAG [237]
Let's say the second piece is x ft long
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x+2x+x+4=10
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What is the product?
marysya [2.9K]

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Step-by-step explanation:

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3 years ago
Order of Operations: Missing Numbers, please help
avanturin [10]
1. Answer is 14.

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5 0
3 years ago
For which value of x is the equation 4x + 24 = 8x + 2x true?
andrew-mc [135]

Answer:

x=4

Step-by-step explanation:

4x+24=8x+2x

We'll combine the 8x and the 2x on the right side.

4x+24=10x

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8 0
3 years ago
Read 2 more answers
HELPPP ASAPPP DUE SOONN
Andru [333]

The friction force exerted on the 2400kg car is 9408 Newtons

<h3>What force will be exerted on the 2400kg car?</h3>

First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:

F = k*M

Where F is the force, M is the mass and k is the constant of proportionality.

We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:

6272N = k*1600kg

Solving for k we get:

k  = (6272N)/(1600 kg) = 3.92 N/kg

Then the proportional relationship is:

F = (3.92 N/kg)*M

So if M = 2400kg, we have:

F = (3.92 N/kg)*2400kg = 9408 N

So the friction force exerted on the 2400kg car is 9408 Newtons

If you want to learn more about proportional realtions:

brainly.com/question/12242745

#SPJ1

8 0
2 years ago
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