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2 years ago

Which transformations could have been used to create A'B'C'? Choose all that apply.

Mathematics

1 answer:

Eduardwww [97]2 years ago

6 0

The correct transformation is a rotation of 180° around the origin followed by a translation of 3 units up and 1 unit to the left.

<h3>Which transformation is used to get A'B'C'?</h3>

To analyze this we can only follow one of the vertices of the triangle.

Let's follow A.

A starts at (3, 4). If we apply a rotation of 180° about the origin, we end up in the third quadrant in the coordinates:

(-3, -4)

Now if you look at A', you can see that the coordinates are:

A' = (-4, -1)

To go from (-3, -4) to (-4, -1), we move one unit to the left and 3 units up.

Then the complete transformation is:

A rotation of 180° around the origin, followed by a translation of 3 units up and 1 unit to the left.

If you want to learn more about transformations:

brainly.com/question/4289712

#SPJ1

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Need help ASAP!!!!!!!!!!!

8090 [49]

Answer:

Step-by-step explanation:

5/6 + 1/8 + 3/4 = 1 17/24

Option A is the correct answer

8 0

3 years ago

Stephen & Richard share a lottery win of £2950 in the ratio 2 : 3. Stephen then shares his part between himself, his wife &a

horsena [70]

Answer:

Stephen's wife got £354 more than his son.

Step-by-step explanation:

Given:

Amount of Lottery = £2950

Now Given:

Stephen & Richard share a lottery amount in the ratio 2 : 3

Let the common factor between them be 'x'.

So we can say that;

$2x+3x=2950\\\\5x = 2950$

Dividing both side by 5 we get;

$\frac{5x}{5}=\frac{2950}{5}\\\\x = 590$

So we can say that;

Stephen share would be = $2x =2\times 590 = \£1180$

Now Given:

Stephen then shares his part between himself, his wife & their son in the ratio 3 : 5 : 2.

Let the common factor between them be 'y'.

So we can say that;

$3y+5y+2y=1180\\\\10y=1180$

Dividing both side by 10 we get;

$\frac{10y}{10}=\frac{1180}{10}\\\\y=118$

So Stephen's wife share = $5y = 5\times 118= \£590$

And Stephen's son share = $2y=2\times118 =\£236$

Now we need to find how much more her wife got then her son.

To find how much more her wife got than her son we will subtract Stephen's son share from Stephen's wife share.

framing in equation form we get;

Amount more her wife got than her son = $590-236 = \£354$

Hence Stephen's wife got £354 more than his son.

3 0

3 years ago

Help me this is hard

siniylev [52]

Following PEMDAS is crucial to solving these. Please Excuse My Dear Aunt Sally

P - Parenthesis

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

Multiplication/Division and Addition/Subtraction are interchangeable.

Now then, number 1 has the following:

$4-2*409-8*96$

There are no parenthesis or exponents, but there is multiplication, so we will start with multiplying. There are two multiplication expressions in the problem.

$-2 * 409 = -818$

$-8 * 96 = -768$

Since you did that, your answer has been simplified to:

$4-818-768$

Now, all you have to do is combine your like terms. Since every term is alike, you can combine the whole expression.

$4-818-768 = -1582$

So, your final answer would be:

$4-2*409-8*96 = -1582$

Hopefully with this information, you can solve the rest. If you have any questions, let me know.

3 0

3 years ago

Ymorist [56]

A. 12 dollars. 84 /7=12

6 0

3 years ago

Read 2 more answers

TV studio has brought in 9 boy kittens and 6 girl kittens for a cat food commercial. The director is going to choose 9 of these

Amanda [17]

Answer:

probability = 0.2517

Step-by-step explanation:

given data

boy kittens = 9

girl kittens = 6

choose kittens at random = 9

solution

total kitten are = 9 + 6 = 15

first we get here total no of probability that is

n(s) = 15 C 9

n(s) = $\frac{15!}{9!(15-9)!}$

n(s) =5005

and

total way to chose 5 boy kittens is = 9 C 3

n(3) = $\frac{9!}{3!(9-3)!}$

n(3) = 84

and

total way to chose 4 girl kittens is = 6 C 4

n(4) = $\frac{6!}{4!(6-4)!}$

n(4) = 15

total way to chose 5 boy kittens and 4 girl kittens is

total way = 84 ×15 = 1260

so probability that the director chooses 5 boy kittens and 4 girl kittens is

probability = $\frac{1260}{5005}$

probability = 0.2517

6 0

3 years ago