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Sergeu [11.5K]
3 years ago
7

Y=-3x+4 solved for y

Mathematics
2 answers:
Sauron [17]3 years ago
7 0
Y= -3x+4   should be 0

vladimir2022 [97]3 years ago
5 0
<span>Y = -3x + 4

this is already in simplest form and solved for y.


</span>
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Describe all of the transformations occurring as the parent function f(x) = x^3 is transformed into g(x) = -0.5(3(x+4))^3 -8
hodyreva [135]

Step-by-step explanation:

The translations of the typical functions are

y = a(bx + c)  + d

Where a is the vertical translation,

If a is greater than 1 or less than -1, we have a vertical stretch

If a is between -1 and 1 , we have a vertical compressions or shrink.

If a is negative, we have a negative reflection across the x axis.

If b is greater than 1 or less than -1, we have a horizontal compression or shrink

If b is between -1 and 1, we have a horizontal stretch

If b is negative, we have a reflection about the y axis,

If c is negative, we have a translation to the right c units

If c is positive, we have a translation to the left c units

If d is positive, we have a translation upward d units

If d is negative, we have a translation downward d units.

Here in this problem, our parent function is x^3.

So I would do the following transformations.

  • Reflect about the x axis
  • Vertical Shrink by a factor of 1/2
  • Horizontal Shrink by a factor of 3
  • Shift to the left 4 units
  • Shift downward 8 units.

4 0
1 year ago
5÷3010 show your work
Ymorist [56]

Answer:

just use a calculator and get 0.00166112956

3 0
3 years ago
What is the value of a(b - c) when b = 3, c = -3 and a = -2?​
musickatia [10]

Answer:

-12

Step-by-step explanation:

a(b - c)

b = 3, c = -3 and a = -2

-2( 3- -3)

-2(3+3)

-2(6)

-12

4 0
3 years ago
Read 2 more answers
If $10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y
algol [13]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47

5 0
3 years ago
Could someone please help me solve this?
ryzh [129]

Answer:

40

Step-by-step explanation:

(2/5)*n - 6 = 10                         Add 6 to both sides

(2/5)*n - 6 + 6 = 10 + 6             Combine

(2/5)*n = 16                               Multiply both sides by 5/2

(5/2)(2/5)n = 16*(5/2)

n = 80 / 2

n = 40  

6 0
2 years ago
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