Hello,
Degre 5==> even number of imaginary roots and odd number of reals.
Real roots must be a divisor of 7.
Using Excel, we find
<span>
<span><span>
x
P(x)
</span><span>-7
0
</span>
<span>
-6
1369
</span>
<span>
-5
1352
</span>
<span>
-4
867
</span>
<span>
-3
400
</span>
<span>
-2
125
</span>
<span>
-1
24
</span><span>0
7
</span><span>1
32
</span><span>2
225
</span><span>3
1000
</span><span>4
3179
</span><span>5
8112
</span><span>6
17797
</span><span>7
35000
So: one real root: 7 and 4 imaginary roots.
Answer B
</span></span></span>
Answer:
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Step-by-step explanation:
Answer:
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A. Evidence. To support a point you would need something to back it up. That being evidence/facts.
