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3 years ago

Can someone help please

Mathematics

1 answer:

vivado [14]3 years ago

7 0

3. A) y-intercept =5
Slope=(-4,10)
B) y=-4/10x+5

4. A) y-intercept=-1
Slope=(5,5)
B) y=5/5x-1

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The distribution of total body protein in healthy adult men is approximately Normal with mean 12.3 kg and standard deviation 0.1

Gelneren [198K]

Answer: a. 0.9876

Step-by-step explanation:

Given : The distribution of total body protein in healthy adult men is approximately Normal with mean 12.3 kg and standard deviation 0.1 kg.

$\mu=12.3$ and $\sigma=0.1$

sample size : n= 25

Let x denotes the total body protein in healthy adult men in the sample.

Then, the probability that their average total body protein is between 12.25 and 12.35 kg will be :-

$P(12.25$

∴ The correct answer is a. 0.9876

4 0

3 years ago

-2.2 + 0.3z= 3 -0.5z -0.8z<br> what does z equal

wariber [46]

$-2.2 + 0.3z= 3 -0.5z -0.8z \\ \\ 0.3z - 2.2 = 3 - 0.5z - 0.8z \\ \\ 0.3z - 2.2 = 3 - 1.3z \\ \\ 0.3z = 3 - 1.3z + 2.2 \\ \\ 0.3z = -1.3z + 5.2 \\ \\ 0.3z + 1.3z = 5.2 \\ \\ 1.6z = 5.2 \\ \\ z = 3.25 \\ \\$

The final result is: z = 3.25.

3 0

3 years ago

Read 2 more answers

The table shows the results of a poll of 200 randomly selected juniors and seniors who were asked if they attended prom. Find th

Zielflug [23.3K]

Answer:

(a) $\frac{7}{25}$

(b) $\frac{19}{116}$

Step-by-step explanation:

Number of juniors who attended prom,n(J)=28

Number of seniors who attended prom,n(S)=97

Total of those who attended prom=125

Number of juniors who did not attend prom,n(J')=56

Number of seniors who did not attend prom,n(S')=19

Total of those who attended prom=75
Total Number of students=200

(a) P (a junior who did not attend prom)

$P(J')=\frac{56}{200}= \frac{7}{25}$

(b)

$P(Senior)=\frac{116}{200}$

$P ($did not attend prom$ | senior)=\frac{\text{P(seniors who did not attend prom)}}{P(Senior)} \\=\frac{19/200}{116/200} \\=\frac{19}{116}$

(c)P (junior | attended prom)

$P(Senior)=\frac{84}{200}$

$P (Junior|$ attended prom$)=\frac{\text{P(juniors who attended prom)}}{P(\text{those who attended prom)}} \\=\frac{28/200}{125/200} \\=\frac{28}{125}$