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Pepsi [2]
2 years ago
8

PLEASE HELP PLEASE PLEASE

Mathematics
2 answers:
snow_lady [41]2 years ago
6 0
A i did this and i got a good grade
jenyasd209 [6]2 years ago
3 0

Answer:

A

Step-by-step explanation:

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80 pts! Solve the equation. <br> Please select the best answer from the choices provided.
Flauer [41]

Answer:

C

Step-by-step explanation:

We can first move the variables to one side.

We can do this by subtracting 6x from both sides.

12x^2-6x=0

Now, we can factor out 6x.

6x(2x-1)=0

Since it equals 0, we know that 2x-1=0, or 6x=0.

This is because when ab=0, either a or b must equal 0.

So we can set both of these equal to 0 to solve.

6x=0

Divide both sides by 6.

x=0

2x-1=0

Add 1 to both sides.

2x=1

Divide both sides by 2.

x=1/2

5 0
3 years ago
For the function y=-1+6 cos(2pi/7(x-5)) what is the minimum value?
Ad libitum [116K]
Usually one will differentiate the function to find the minimum/maximum point, but in this case differentiating yields:
\frac{2\pi}{7(x-5)^{2}}\sin{\frac{2\pi}{7(x-5)}}}
which contains multiple solution if one tries to solve for x when the differentiated form is 0.

I would, though, venture a guess that the minimum value would be (approaching) 5, since the function would be undefined in the vicinity.

If, however, the function is
-1+\cos{\frac{2\pi}{7}(x-5)}}
Then differentiating and equating to 0 yields:
\sin{\frac{2\pi}{7}(x-5)}}=0
which gives:
x=5 or 8.5

We reject x=5 as it is when it ix the maximum and thus,
x=8.5\pm7n, for n=0,\pm 1,\pm 2, ...
3 0
3 years ago
Read 2 more answers
Simplify each equation <br> (x^4)(x^2)
BartSMP [9]
Ok, so remember the exponentioal law that says
( x^{m} )(x^{n})=x^{m+n} so


( x^{4} )(x^{2})=x^{4+2}= x^{6}

answe ris x^6
5 0
3 years ago
Read 2 more answers
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
4 years ago
What is 11 1/20 as a decimal?
Softa [21]

11,05

Step-by-step explanation:

11 1/20

= (11 × 20 + 1)/20

= (220 + 1)/20

= 221/20 → times 5

= 1105/100

= 11,05

5 0
2 years ago
Read 2 more answers
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