All categories

3 years ago

What exact area of a circle with a radius of 6 feet?

Mathematics

1 answer:

Volgvan3 years ago

7 0

Answer:

Step-by-step explanation:

3.14(pi) X 6 ^2 =

3.14*6 = 18.84

3.14x6^2 =36

your final answer is : B. : 36

You might be interested in

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago

What is the circumference of a circle with a radius of 0.8 m? A. 0.64*pi m B. 0.8*pim C. 1.6*pi m D. 2.56*pi m

Paraphin [41]

C = 2πr
C = 2(3.14)(0.8)
C = 2(2.512)
C = 5.024 m

The answer is C.

7 0

3 years ago

Copy and complete the workings to find the value of each expression when m=2 and p=-4

dolphi86 [110]

Answer:

- 24

Step-by-step explanation:

4(m + 2p) ← substitute m = 2 and p = - 4 into the expression

= 4(2 + 2(- 4) )

= 4(2 - 8)

= 4(- 6)

= - 24

6 0

2 years ago

HELP<br> Write an equation of a line passing through (-8, 6) and parallel to the line y=-4x - 1

MArishka [77]

The line is parallel so it has the same slope as the other line, -4.

Substitute the x and y variables with the given points and find the y-intercept.

(-8, 6)

y = -4x + b

6 = -4(8) + b

6 = -32 + b

6 + 32 = b

38 = b

So the equation is:

y = -4 + 38

4 0

3 years ago

Need Help For This Question

Neko [114]

Answer:

The Answer is B

Step-by-step explanation:

+7 at the end means up 7

The - 4 in the middle represents right 4

These are found using basic rules of translating equations

6 0

3 years ago

Read 2 more answers