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hjlf
2 years ago
7

Which values from this set {−12, −9, −3, 0, 3, 6} satisfy this inequality?

Mathematics
1 answer:
Vesna [10]2 years ago
7 0

The values -3, -9 and -12 satisfy the inequality.

In this question we evaluate each element of the set to determine whether value belongs to the inequation given on statement:

x = 0

-13\cdot 0 + 3 \ge 6

3\ge 6 (FALSE)

x= -3

-13\cdot (-3) +3 \ge 6

42\ge 6 (TRUE)

x = -9

-13\cdot (-9)+3 \ge 6

120\ge 3 (TRUE)

x = -12

-13\cdot (-12) +3 \ge 6

159 \ge 6 (TRUE)

The values -3, -9 and -12 satisfy the inequality.

We kindly invite to see this question on inequalities: brainly.com/question/17675534

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The 6 boys in Ms.dreyvus’ class always ran together during recess.
mr_godi [17]

Answer:

36 miles each

Step-by-step explanation:

you divide 192 by 6 = 36

hope this helps

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8 0
3 years ago
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The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction
Len [333]

Answer:

(a) <em>                             </em><em>n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.

Assuming that the random variable <em>X </em>follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

  • For a sample size of <em>n</em> = 20

P(\mu-200

                                           =P(-0.37

  • For a sample size of <em>n</em> = 50

P(\mu-200

                                           =P(-0.59

  • For a sample size of <em>n</em> = 100

P(\mu-200

                                           =P(-0.83

  • For a sample size of <em>n</em> = 500

P(\mu-200

                                           =P(-1.86

<em>                                  n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample (\bar x) approaches the whole population mean (\mu_{x}).

Consider the probabilities computed in part (a).

As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.

So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.

Thus, the correct option is (b).

8 0
3 years ago
Which of the following expressions is equivalent to -9?
FromTheMoon [43]

B because there is only one negative and -63 divided by 7 equals -9. If it were -7 divided by 63 that would give you an answer in decimal form.

6 0
3 years ago
Which of the following is a factor of 24x6 − 1029y3?
amid [387]

Answer:

The answer to your question is only the second and the third are factors.

Step-by-step explanation:

Find the factors of               24x⁶ − 1029y³

First find the prime factors of 24 and 1029

  24  2                1029 3

  12   2                  343 7                  Then 24 = 2³3

   6   2                    49  7                         1029 = 7³ 3

   3   3                       7  7

   1                             1

     x⁶ = (x²)³                  y³ = y³

Then

                                  2³3(x²)³  -  7³ 3  y³

Factor 3                    3[  2³(x²)³  -  7³ y³]

Factor                      3 [ (2x² - 7y)(4x⁴ + 14x²y + 49y²)]

Then

24

2x2 + 7y

4x4 + 14x2y + 49y2

All of the above

8 0
3 years ago
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What is 7.8 x 10^5 hours in days?
dimaraw [331]

<em>3.250 x 10^4, </em><em>will be the correct answer.</em>

Thanks,

<em>Deku ❤</em>

3 0
3 years ago
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