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3 years ago

Please help me...asap

Mathematics

1 answer:

Ivahew [28]3 years ago

4 0

(2nd option) yes, each number has an equal chance of being selected.

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Two trains, Train A and Train B, weigh a total of 318 tons. Train A is heavier than Train B. The difference of their weights i

alukav5142 [94]

Answer:

ohyou already got an answer

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

if any one can help me that would be awesome 1. − 8 = 5 b − 3 b 2. k − 8 + 6 k = 20 3. 723. 4. 6 ( 3 + 3 x ) = 72 364. 5 ( m + 4

Morgarella [4.7K]

Answer:

1)b=-4

2)k=4

3)can u explain what #3 and 4 say

4)?

5)0/ no solution

Step-by-step explanation:

5 0

4 years ago

How many significant figures does 0290<br> have?

docker41 [41]

Two significant figures.
The trailing zero is not significant

7 0

4 years ago

Select the correct answer from the drop-down menu.

ZanzabumX [31]

Answer:

The answer to your question is y = 4 - 1.5x

Step-by-step explanation:

Data

River's speed = 2 mi/h

David's speed = 6 mi/h

Rate of change = 1.5 mi/h

From the data given, we can conclude that the rate of the boat will be the difference between David's speed and the speed of the boat = 4mi/h.

The slope must be negative because it decreases.

The only equation that satisfies both conditions is the second option.

5 0

4 years ago

A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal

Julli [10]

Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals $0.0003724L_{i}$ where $L_{i}$ is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

$\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}$

We have

$\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}$

Applying values we get

$\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}$

Similarly axial strain is given by

$\epsilon _{diam}=\frac{\sigma _{axial}}{E}$

$\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}$

Applying values we get

$\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}$