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3 years ago

It’s is integer fractions in 7th grade mathematics

Mathematics

1 answer:

Goryan [66]3 years ago

3 0

Can you post a picture of your question? I can help

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8. y 5 х -5 Ut --5 slope = Please help me

Burka [1]

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3 years ago

At the beginning of April, Owl Corporation has a balance of $12,000 in the Retained Earnings account. During the month of April,

Katarina [22]

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3 years ago

Please help!! Question is in the picture!!

Debora [2.8K]

$\frac{17}{60}$ and $\frac{1}{4}$ are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

Experimental probabilities from the table:

Probability of getting 1 = $\frac{12}{60}=\frac{1}{5}$

Probability of getting 2 = $\frac{17}{60}$

Probability of getting 3 = $\frac{15}{60}=\frac{1}{4}$

Probability of getting 4 = $\frac{16}{60}=\frac{4}{15}$

To determine which are the experimental probabilities from the table:

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: $\frac{17}{60}$

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: $\frac{1}{4}$

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: $\frac{7}{15}$

This is not obtained above. So, it is not the experimental probability.

Option E: $\frac{12}{43}$

This is not obtained above. So, it is not the experimental probability.

Hence $\frac{17}{60}$ and $\frac{1}{4}$ are the experimental probabilities from the table.

5 0

3 years ago

Can I get help finding the value of m and n

Marina86 [1]

9514 1404 393

Answer:

m = 35

n = 110

Step-by-step explanation:

Adjacent angles in a parallelogram are supplementary.

n° = 180° -70°

n = 110

Opposite angles in a parallelogram are congruent.

2m° = 70°

m = 35 . . . . . . divide by 2°

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3 years ago

Help please i don’t know how to do it

Norma-Jean [14]

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=x^{2}(y-1)\\\frac{1}{y-1} \text{ } dy=x^{2} \text{ } dx\\\int \frac{1}{y-1} \text{ } dy=\int x^{2} \text{ } dx\\\ln|y-1|=\frac{x^{3}}{3}+C\\$

From the initial condition,

$\ln|3-1|=\frac{0^{3}}{3}+C\\\ln 2=C$

So we have that $\ln |y-1|=\frac{x^{3}}{3}+\ln 2\\e^{\frac{x^{3}}{3}+\ln 2}=y-1\\2e^{\frac{x^{3}}{3}}=y-1\\y=2e^{\frac{x^{3}}{3}}+1$

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3 years ago