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Citrus2011 [14]

4 years ago

9

The width of a rectangle is 20 inches. What must the length be if the perimeter is at least 180 inches.a 85.5 inches b 70 inches

c 75 inches d 69.5 inches and e 55 inches

1 answer:

Veronika [31]4 years ago

5 0

The anwser is b 75 inches

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The square prism has a base length of 2 ft. Which describes the cross section of the prism that iS perpendicular to the

Anon25 [30]

Answer:

A-a rectangle with two 12-ft sides and two 2-ft sides

Step-by-step explanation:

Got it right on edge

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3 years ago

Which two ratios show a proportional relationship?

olga2289 [7]

The answer is B ahaha

5 0

4 years ago

If 9<15mx-8<279<15mx−8<279, is less than, 15, m, x, minus, 8, is less than, 27, where mmm is a positive constant, wh

rewona [7]

Answer:

The range of $\frac{8}{3}-5mx$ is (-9,-3).

Step-by-step explanation:

The given compound inequality is

$9$

We need to find the range of values of $\frac{8}{3}-5mx$ .

Let $y=\frac{8}{3}-5mx$

Divide each side of the given compound inequality by 3.

$\frac{9}{3}$

$3$

$3$

Multiply each side by -1.

If we multiply an inequality by a negative number, then the sign of inequality is changed.

$3(-1)>(5mx-\frac{8}{3})(-1)>9(-1)$

$-3>-5mx+\frac{8}{3}>-9$

$-3>\frac{8}{3}-5mx>-9$

$-3>y>-9$

Therefore the range of $\frac{8}{3}-5mx$ is (-9,-3).

5 0

3 years ago

5x-3y=20 line perpendicular

Galina-37 [17]

Answer:

y=(-3/5)x

Step-by-step explanation:

5x-3y=20

-3y=-5x+20

y=(5/3)x-(20/3)

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5 0

3 years ago

Read 2 more answers

A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo

Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

a)

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) $10X+5X+5X=300 => 20X = 300 => X = 15$ days for the lessons

b) $5X+10X+8X = 300 => 23X = 300 => X = 13.04$ days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) $10X+5X=300 => 15X = 300 => X = 20$ days for the lessons

b) $5X+10X = 300 => 15X = 300 => X = 20$ days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) $10(10/24)+5X+5X= 300 => X = 29.58$ days for the lessons

b) $5(10/24)+10X+8X = 300 => X = 16.51$ days for the tests

so at the end to complete both tasks they need 29.58 days

4 0

3 years ago