Answer:
The correct one is b nice you chose the right one!
Step-by-step explanation:
Answer:
120
Step-by-step explanation:
10 choose 3
theres really no simple way to do that with work unless you have a fancy calculator.
In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
Hi,
Negative, - 1/3 - 4/5 is subtracting a positive from a negative making it still a negative
So for something to be perpendicular the gradient must be the negative reciprocal of your original line so your original gradient is 2 so your new gradient will be -1/2. Then you have y = -1/2 x + c . Now you substitute this into the point (4,-1) to get -1 = -1/2 x 4 + c and -1/2 x 4 = -2 so you have -1 = -2 + c so c = 1 so then you put the equation together to get y = -1/2 x + 1
Hope this helps :))