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Darina [25.2K]
3 years ago
15

Can Someone Help Me With a Few Math Questions?

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0
Yes, yes I can. But post them please haha
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A couple has four children. what is the probability that they would have four boys?
Ivahew [28]

Answer:1/6

Step-by-step explanation:

7 0
2 years ago
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How you substract 7 from 52
ioda
52-7 which equals 45
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3 years ago
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Q and r are independent events. if p(q) = 1/4 and p(r)=1/5, find p(q and r)
klasskru [66]

Answer:

(b) \frac{7}{30}

Step-by-step explanation:

When two p and q events are independent then, by definition:

P (p and q) = P (p) * P (q)

Then, if q and r are independent events then:

P(q and r) = P(q)*P(r) = 1/4*1/5

P(q and r) = 1/20

P(q and r) = 0.05


In the question that is shown in the attached image, we have two separate urns. The amount of white balls that we take in the first urn does not affect the amount of white balls we could get in the second urn. This means that both events are independent.


In the first ballot box there are 9 balls, 3 white and 6 yellow.

Then the probability of obtaining a white ball from the first ballot box is:

P (W_{u_1}) = \frac{3}{9} = \frac{1}{3}

In the second ballot box there are 10 balls, 7 white and 3 yellow.

Then the probability of obtaining a white ball from the second ballot box is:

P (W_{u_2}) = \frac{7}{10}

We want to know the probability of obtaining a white ball in both urns. This is: P(W_{u_1} and W_{u_2})  

As the events are independent:

P(W_{u_1} and W_{u_2})  = P (W_{u_1}) * P (W_{u_2})

P(W_{u_1} and W_{u_2})  = \frac{1}{3}* \frac{7}{10}

P(W_{u_1} and W_{u_2})  = \frac{7}{30}

Finally the correct option is (b) \frac{7}{30}

3 0
2 years ago
Can you find the area for this?
Damm [24]

Answer:

I think it's C) 18.5ft^2

it's just an educated guess though I haven't worked on area in a while

7 0
2 years ago
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A farmer has a truckload of watermelons to take to market. At the beginning of the trip, the watermelons weigh 1000 kg. 99% of t
Mariulka [41]

Answer:

The weight of watermelon at the end of the trip is <u>500 kg.</u>

Step-by-step explanation:

Given:

The weight of watermelons is 1000kg.

At the beginning of the trip watermelon is 99% of the weight:

99% of 1000kg

\frac{99}{100}\times 1000

=0.99\times 1000

= 990 kg

Now, at the end of the trip it is 98% of weight. So, let x kg of water has been evaporated. So, remaining weight of the watermelon is 1000-x.

If x kg of water is removed, then the amount of water left is 990-x.

As per question, water now weighs 98% of the total weight. So,

98% of (1000-x) = 990-x

\frac{98}{100}\times (1000-x)=990-x

980-0.98x=990-x

-0.98x+x=990-980 (Bringing like terms on one side)

0.02x=10\\x=\frac{10}{0.02}=500\ kg

Therefore, the weight of watermelon at the end of the trip is given as:

Weight = 1000 - x = 1000 - 500 = 500 kg

Therefore, the watermelon weighs 500 kg at the end of trip.

7 0
3 years ago
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