X+y= -12
xy=8
y=8/x
x+8/x=-12
x^2+12x+8=0
This has no integral
Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
Option D. 1
Option E. 1/2
Step-by-step explanation:
we know that
Looking at the graph
The domain is the interval ----> [-1,1]
The domain is all real numbers greater than or equal to -1 and less than or equal to 1
The range is the interval ----> [0,1]
The range is all real numbers greater than or equal to 0 and less than or equal to 1
therefore
The values that are in the range are
1 and 1/2
The bottom two because they rapidly go up or down super fast. If it’s an exponential function, it will start off as super low or super high and then shoot up or down rapidly
Yes because if you distribute the 3 and multiply it with 3 • x and 3• 6 you’ll get 3x-18