Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>
Step-by-step explanation:
The intercept form of a quadratic equation (parabola):
p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
The Solution for the given system of equations is (-2) and 
.
The given are linear equations as follow:
y = 
+ 3 .. ... ...(1)
and x = -2. .. .... ...(2)
We already know the first part of the solution (x) which is -2. We can find the other part (y) by putting the value of equation (2) in equation (1).
By putting the values of x in equation (1), we get
y = 
+ 3
y = 
+ 3
Taking the L. C. M of denominators which will be '3', we get:
y = 
y = 
So the second part (y) of the solution of the given equation is .
Hence, the overall solution to the given system of equation is 
.
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The sum of 2a and 3b:
2a + 3b
Answer:
x= -13
y= -28
Step-by-step explanation:
To find the two numbers, write a system of equations with x as one number and y as another:
x-y=15
5x=2y-9
Use substitution to substitute one equation into another. Then solve for the variable.
x=15+y into 5x=2y-9
becomes
5(15+y) = 2y-9
75+5y = 2y- 9
75+3y= -9
3y = -84
y= -28
To find x, substitute y= -28 into one equation.
x - (-28) = 15
x+28 =15
x = 15-28
x=-13
3y=2(2+2y); 3y=4+4y; -y=4; y=-4;
