Answer:
<em>The true statements are:</em>
<em>*The median weight for shelter A is greater than shelter B.</em>
<em>*The (IQR) interquartile range of shelter A is greater than the (IQR) interquartile range of shelter B.</em>
Step-by-step explanation:
<em>(for shelter A)</em>
median: 21
lowest value: 8
highest value: 30
lower quartile: 17
upper quartile: 28
(IQR) interquartile range: 28 - 17 = 11
Range: 30 - 8 = 22
<em>(for shelter B)</em>
median: 18
lowest value: 10
highest value: 28
lower quartile: 16
upper quartile: 20
(IQR) interquartile range: 20 - 16 = 4
Range: 28 - 10 = 18
~phew!, this took me long xd, hope this helps you~
I would highly appreciate it if you would mark me the brainliest~ :)
Answer:
a. the less variability it has
Step-by-step explanation:
The standard deviation is a measure of the amount of variation or dispersion of a set of values.
When your standard deviation is big your data is more dispersed.
When your standar deviation is small your mean is a representative index of your data, and there is less variability.
If there was no dispersion of the data (if all your data be the same) then the standard deviation will be 0.
The travels you have described are:
(Middle floor) + 8 + 5 - 9 + 7 - 32
= (middle floor) + 20 - 41
= (middle floor) - 21 brought her to floor #1.
So Middle floor - 21 = 1
Add 21 to each side: Middle floor = 22
The building has (2 x middle floor) = 44 floors.
First distribute the 2, then add 7 to that side, so you have 2g+17=-4g+g , subtract 2g and it should be easy to find from there lol
Answer: [0, 396]
Step-by-step explanation:
The domain is the acceptable values of x in the function. In this case, x = t, the number of tiles. If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles). So, the domain for this function is from 0 to 44.
0 to 44 written in interval notation is [0,44].
The range is the acceptable values of y in the function. In this case, y = A, the area given. A(t) = 9t, so you can use the acceptable values of t to get the range. Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.
A(t) = 9t
A = 9(44)
A = 396
With the maximum number of tiles, 44, the area you get is 396 cm². Therefore, the acceptable values of A are from 0 to 396.
0 to 396 written in interval notation is [0, 396].
