The power P(x) carried by this wave at a point x = P(x) = (μ ω³ A² e⁻²ᵇˣ)/2k
Power time is the pace at which work is completed or energy is delivered; it is expressed as the product of the work completed (W) and the energy transferred (t), or W/t. The variation in the gas pressure ΔP measured from the equilibrium value is also periodic with the same wave number and angular frequency as for the displacement which is given by
ΔP = ΔPmax sin (kx−ωt)
Power is an expression of energy expended through time (effort), of which force is an element, as opposed to force itself, which is the fundamental outcome of an interaction between two objects. Power can be measured and described, but a force is a real physical entity, but power is not. The power is the rate at which the piston is doing work on the element at any instant of time is given by
Power = F ⋅ v
As we mention before in the concept session, the power of the wave is given by
P = ρ ν ω² A s² sin(kx-ωt)
P(x) = 1/2 μ ω² ν A²
= 1/2 μ ω² ω/2 A² e⁻²ᵇˣ
P(x) = (μ ω³ A² e⁻²ᵇˣ)/2k
So, The final answer of power P(x) is P(x) = (μ ω³ A² e⁻²ᵇˣ)/2k.
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Answer:
Explanation:
<em>Work </em>is the change in kinetic energy and may be calculated as the product of the force in the direction of the displacement times the displacement.
For a differential displacement, Δx, and a variable force, f(x), the differential work done is:
And the total work done from a point xi to xf is:
Thus, for this problem we have:
- f(x) =
The symbol is just indicating that the direction of the force is in the same direction of the displacement.
Integrating you get:
And that is 54.8697 joules (since the units for x are meter and the units for f(x) are newtons).
Rounded to two significant digits: 55 joules.