Question

If you fire a projectile from the ground, it hits the ground some distance R away (called "the range"). If you keep the launch angle fixed, but double the initial launch speed, what happens to the range?

Answer 1

Answer:

range becomes 4 times

Explanation:

We know that the range of a projectile is given as:

$R=\frac{u^2.\sin(2\theta)}{g}$

where:

$R=$ range of the projectile

$u=$ initial velocity of projectile

$\theta=$ initial angle of projection form the horizontal

g = acceleration due to gravity

When the initial velocity of launch is doubled:

$R'=\frac{(2u)^2.\sin(2\theta)}{g}$

$R'=\frac{4u^2.\sin(2\theta)}{g}$

$R'=4R$

range becomes 4 times