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ella [17]
4 years ago
13

If you fire a projectile from the ground, it hits the ground some distance R away (called "the range"). If you keep the launch a

ngle fixed, but double the initial launch speed, what happens to the range?
Physics
1 answer:
Zanzabum4 years ago
3 0

Answer:

range becomes 4 times

Explanation:

We know that the range of a projectile is given as:

R=\frac{u^2.\sin(2\theta)}{g}

where:

R= range of the projectile

u= initial velocity of projectile

\theta= initial angle of projection form the horizontal

g = acceleration due to gravity

When the initial velocity of launch is doubled:

R'=\frac{(2u)^2.\sin(2\theta)}{g}

R'=\frac{4u^2.\sin(2\theta)}{g}

R'=4R

range becomes 4 times

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