Answer:

Step-by-step explanation:
Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.
we have to find the length of AB.
Let the side of square i.e AB is x units.
As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°
⇒ CP||MP||AB
In ΔMNP and ΔCND
∠NCD=∠NMP (∵ corresponding angles)
∠NDC=∠NPM (∵ corresponding angles)
By AA similarity rule, ΔMNP~ΔCND
Also, ΔKAP~ΔKPM by similarity rule as above.
Hence, corresponding sides are in proportion



Adding above two, we get

⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
I do not the question. Please explain
For a.
Since there are already two angles given for the triangle, we can measure the last angle using this formula:
90 + 55 + a = 180
Now solve for "a".
90 + 55 + a = 180
145 + a = 180
a = 180 - 145
a = 35°
For b.
From the picture above, the two triangle's tip are touching and having to form <em>vertical angles. </em>This means that the angles are congruent to each other.
Now that we have two angles in the second triangle(35 and 120), we can use the same formula:
35 + 120 + b = 180
Now solve for "b":
35 + 120 + b = 180
155 + b = 180
b = 180 - 155
b = 25°
Y=1/4x-3
1/4x is rise over run or you go up or down then you go left or right. Since this is a positive line you will go up 1 and right 4. The -3 is the point in the y-axis that the line goes through