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Kruka [31]
4 years ago
12

NO LINKS OR I WILL REPORT but helppp plsss A triangle has two sides of length 3 and 3. What value could the length of the

Mathematics
1 answer:
Studentka2010 [4]4 years ago
7 0
<h3>3 answers: Choice A), Choice C), Choice D)</h3>

========================================================

Explanation:

We have a triangle with sides a,b,c where a = 3 and b = 3 are given. The side c is unknown, but using the variation of the triangle inequality theorem allows us to say the following:

b-a < c < b+a

3-3 < c < 3+3

0 < c < 6

The missing side c is between 0 and 6 units long, but cannot be equal to 0 and can't be equal to 6 either. Therefore, the answers must be A) 4, C) 5, and D) 2. All of these values satisfy the inequality 0 < c < 6.

Something like c = 12 is too large. I recommend cutting out two slips of paper that are 3 inches long, and you'll find it impossible to form a triangle that has a third side of 12 inches. The longest side you can form is 3+3 = 6 inches, but you wouldn't have a triangle at that point (it would be a straight line instead). This is a visual way to rule out choice E, and it also rules out choices B and F for similar reasoning.

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denis23 [38]

So firstly, factor out h on the left side: h(b+r)=25

Next, divide both sides by h: b+r=\frac{25}{h}

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You have 45 more days of school left. How many years is that?
Ronch [10]

Answer:

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Step-by-step explanation:

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3 years ago
Helpp!!!<br>(1-sin2A)(1+cot2A)=cot2A​
lord [1]

This isn't an identity, so I assume you have to solve the equation.

(1 - sin(2<em>A</em>)) (1 + cot(2<em>A</em>)) = cot(2<em>A</em>)

1 - sin(2<em>A</em>) + cot(2<em>A</em>) - sin(2<em>A</em>) cot(2<em>A</em>) = cot(2<em>A</em>)

1 - sin(2<em>A</em>) - cos(2<em>A</em>) = 0

sin(2<em>A</em>) + cos(2<em>A</em>) = 1

Multiply both sides by 1/√2, which we want to do because cos(<em>π</em>/4) = sin(<em>π</em>/4) = 1/√2. This gives

cos(<em>π</em>/4) sin(2<em>A</em>) + sin(<em>π</em>/4) cos(2<em>A</em>) = 1/√2

Then condense the left side as

sin(2<em>A</em> + <em>π</em>/4) = 1/√2

2<em>A</em> + <em>π</em>/4 = sin⁻¹(1/√2) + 2<em>nπ</em>  <u>or</u>   2<em>A</em> + <em>π</em>/4 = <em>π</em> - sin⁻¹(1/√2) + 2<em>nπ</em>

(where <em>n</em> is any integer)

2<em>A</em> + <em>π</em>/4 = <em>π</em>/4 + 2<em>nπ</em>  <u>or</u>   2<em>A</em> + <em>π</em>/4 = 3<em>π</em>/4 + 2<em>nπ</em>

2<em>A</em> = 2<em>nπ</em>  <u>or</u>   2<em>A</em> = <em>π</em>/2 + 2<em>nπ</em>

<em>A</em> = <em>nπ</em>  <u>or</u>   <em>A</em> = <em>π</em>/4 + <em>nπ</em>

4 0
3 years ago
Order the numbers from least to greatest.
lakkis [162]
Easiest way to do this is to turn them all to decimals

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2.5= 2.5
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order least to greatest:
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2.23
2.5
8 0
3 years ago
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