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3 years ago

What's the expanded notation for 876,543,210.25?

2 answers:

8 0

876,543,210.25 = 8(100,000,000) + 7(10,000,000) + 6(1,000,000) + 5(100,000) + 4(10,000) + 3(1,000) + 2(100) + 1(10) + 2(0.1) + 5(0.01)

Sunny_sXe [5.5K]3 years ago

7 0

800,000,000.00+70,000,000.00+6,000,000.00+500,000.00+40,000.00+3,000.00+200.00+10.00+0.00+0.20+0.05

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What is the graph of the equation y-3=2(x+3)

arsen [322]

Answer:

y−3=2(x+3)

y=2x+9

that's the answer hope this helps u

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2 years ago

Need this very badly

NeTakaya

((5x5)/2)x2=50 square ft
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3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers

Find n(A) for A={0,1,2,3,...,2000}

miskamm [114]

There are 2001 items in that set.

So n(A) = 2001

We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1

where,
m = starting value
n = ending value

In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001

This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)

7 0

3 years ago

Pls help im talkin 25 here

leva [86]

Answer: i do know girl

5 0

3 years ago