His new time compared with the old time was increased by factor of 2
<h3>Further explanation</h3>
Acceleration is rate of change of velocity.
![\large {\boxed {a = \frac{v - u}{t} } }](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7Ba%20%3D%20%5Cfrac%7Bv%20-%20u%7D%7Bt%7D%20%7D%20%7D)
![\large {\boxed {d = \frac{v + u}{2}~t } }](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7Bd%20%3D%20%5Cfrac%7Bv%20%2B%20u%7D%7B2%7D~t%20%7D%20%7D)
<em>a = acceleration (m / s²)v = final velocity (m / s)</em>
<em>u = initial velocity (m / s)</em>
<em>t = time taken (s)</em>
<em>d = distance (m)</em>
Let us now tackle the problem!
This problem is about Kinematics.
In this problem we assume that the unicorn is moving at a constant speed so that the acceleration is zero.
<u>Given:</u>
first distance = d₁ = 50 miles
second distance = d₂ = 300 miles
v₂ = 3 v₁
<u>Unknown:</u>
t₂ : t₁ = ?
<u>Solution:</u>
To find his new time , we will use the following formula.
![v_2 = 3 v_1](https://tex.z-dn.net/?f=v_2%20%3D%203%20v_1)
![\frac{d_2}{t_2} = 3 \times \frac{d_1}{t_1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd_2%7D%7Bt_2%7D%20%3D%203%20%5Ctimes%20%5Cfrac%7Bd_1%7D%7Bt_1%7D)
![\frac{300}{t_2} = 3 \times \frac{50}{t_1}](https://tex.z-dn.net/?f=%5Cfrac%7B300%7D%7Bt_2%7D%20%3D%203%20%5Ctimes%20%5Cfrac%7B50%7D%7Bt_1%7D)
![\frac{300}{t_2} = \frac{150}{t_1}](https://tex.z-dn.net/?f=%5Cfrac%7B300%7D%7Bt_2%7D%20%3D%20%5Cfrac%7B150%7D%7Bt_1%7D)
![t_2 = \frac{300}{150} \times t_1](https://tex.z-dn.net/?f=t_2%20%3D%20%5Cfrac%7B300%7D%7B150%7D%20%5Ctimes%20t_1)
![\large {\boxed {t_2 = 2 \times t_1} }](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7Bt_2%20%3D%202%20%5Ctimes%20t_1%7D%20%7D)
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Mathematics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel