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astra-53 [7]
3 years ago
12

Mary has rehearsed her ballet solo for five and a half hours. A week from now, she wants to have rehearsed at least a total of n

ineteen and a half hours. If she rehearses for the same amount of time each day for the next 7 days, at least how many hours must she rehearse per day?
Mathematics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

Step-by-step explanation:

19.5 - 5.5 = 14

14 / 7 > = <u>2</u> hours per day

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When Felix started his paper route, he had 25 customers. Every second week he gained 2 new customers. Every third week he lost a
amid [387]

Answer:

29

Step-by-step explanation:

srry took a sec

6 0
3 years ago
Which is an equation of the line that goes through the points ( 4, 1) and
Aloiza [94]

Answer:

  none of the above

Step-by-step explanation:

You can try the points in the equations (none works in any equation), or you can plot the points and lines (see attached). <em>You will not find any of the offered answer choices goes through the given points</em>.

___

You can start with the 2-point form of the equation of a line. For points (x1, y1) and (x2, y2) that equation is ...

  y = (y2 -y1)/(x2 -x1)·(x -x1) +y1

Filling in the given points, we get ...

  y = (3 -1)/(2 -4)·(x -4) +1

  y = 2/(-2)(x -4) +1 . . . . . simplify a bit

  y = -x +4 +1 . . . . . . . . . simplify more

  y = -x +5 . . . . . . . . . . . slope-intercept form

5 0
3 years ago
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
The height of a triangle is 8 centimeters greater than half its base. The area of the triangle is 48 square centimeters what is
emmainna [20.7K]

Answer:

base = 8 cm

height = 12 cm

Step-by-step explanation:

We will need the formula for area of a trianlge, which is

A = (1/2)bh    where b is the base, and h is the height

We are given two formulas...

"The height of a triangle is 8 centimeters greater than half its base" becomes

  h = (1/2)b + 8

"The area of the triangle is 48 square centimeters" becomes

48 = (1/2)bh

Plug the first formula into the second to solve for h

48 = (1/2)b[(1/2) + 8]             (h becomes (1/2)b + 8)

Now solve for b

48 = (1/4)b² + 4b

**This is a quadratic euquation.  Solve using factoring...

(1/4)b² + 4b - 48 = 0       (subtract 48 from both sides)

b² + 16b - 192  =  0       (multiply by 4 so b² is by itself, it's easier to factor this way)

Now factor...

(b + 24)(b - 8) = 0       (you need two numbers that add to 16 and multiply to -192)

Set each binomial equal to zero and solve for b

b + 24 = 0          

    b = -24    

**this anwser is not valid because b is a length, and you can't have negative length

b - 8 = 0

  b = 8        

Since the other solution is invalid, the base is b

If the base is b, then the height is...

h = (1/2)b + 8

 

   h = (1/2)(8) + 8

     h = 4 + 8

 

         h = 12

8 0
4 years ago
15/60=3/4 are they equivalent
Dvinal [7]
15/60 simplified is 1/4

1/4 is not equal to 3/4
4 0
3 years ago
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