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2 years ago

Helpp ill mark brainliest

Mathematics

2 answers:

Maksim231197 [3]2 years ago

6 0

the three you have marked is right

bija089 [108]2 years ago

3 0

Answer:

the three you have marked are right because you get is cheacked for credit accounts and for late payments

Step-by-step explanation:

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HELPP+ I NEED THIS DONE IN 3 MINUTES PLEASE HELP ME GOD BELIVES IN YOU

alekssr [168]

Answer:

$80$ $%$ $\%$

8 0

2 years ago

Read 2 more answers

=0.56x−0.25n=0.20x−0.03

katovenus [111]

Given:

$m=0.56x-0.25$

$n=0.20x-0.03$

To find:

The sum of m and n.

Solution:

We have,

$m=0.56x-0.25$

$n=0.20x-0.03$

The sum of m and n is:

$m+n=(0.56x-0.25)+(0.20x-0.03)$

Combining the like terms, we get

$m+n=(0.56x+0.20x)+(-0.25-0.03)$

$m+n=(0.76x)+(-0.28)$

$m+n=0.76x-0.28$

Therefore, the sum of m and n is $m+n=0.76x-0.28$ .

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2 years ago

The Sine Function

Zanzabum

Answer:

B. 1.093

Step-by-step explanation:

I calculated it logically

4 0

2 years ago

What is the length of the longest possible laser beam he could send rounded to the nearest tenth of an inch?

Ludmilka [50]

Where is the diagram????????

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2 years ago

Suppose p(a) = 0.40 and p(a 

sveticcg [70]

Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

$P(A\cup B)+P(A\cap B)=P(A)+P(B)$

For parts (a) and (b), you're given everything you need to determine $P(B)$ .

For part (c), if $A$ and $B$ are mutually exclusive, then $P(A\cap B)=0$ , so $P(A\cup B)=P(A)+P(B)$ . If the given probability is $P(A\cup B)=0.55$ , then you can find $P(B)=0.15$ . But if this given probability is for the intersection, finding $P(B)$ is impossible.

For part (d), if $A$ and $B$ are independent, then $P(A\cap B)=P(A)\cdot P(B)$ .

8 0

3 years ago